Javascript private member on prototype

Question

Well I tried to figure out is this possible in any way. Here is code:

a=function(text)
{
   var b=text;
   if (!arguments.callee.prototype.get)
      argumen         


        

Answer 1

I know this thread is really really old now, but thought this solution might be of interest to anyone passing by:

const Immutable = function ( val ) {
    let _val = val;

    this.$ = {
        _resolve: function () {
            return _val;
        }
    };
};
Immutable.prototype = {
    resolve: function () {
        return this.$._resolve();
    }
};

Essentially hiding the internal _val from being manipulated and making an instance of this object immutable.