I want to find the maximum of a nested array, something like this:
a = [[1,2],[20,3]]
d3.max(d3.max(a)) // 20
but my array contains a text
It's a cruel hack, but looking at the source code for d3.max, your best bet might be to define a d3.max1 that discards the first element by copying that code, but replacing i=-1 with i=0. The code at that link is excerpted here. Note that I'm not a regular d3.js user, but from what I know of the library, you're going to want make sure your version has an f.call case like this function does, so that it can respond to live updates correctly.
d3.max = function(array, f) {
var i = -1,
n = array.length,
a,
b;
if (arguments.length === 1) {
while (++i < n && ((a = array[i]) == null || a != a)) a = undefined;
while (++i < n) if ((b = array[i]) != null && b > a) a = b;
} else {
while (++i < n && ((a = f.call(array, array[i], i)) == null || a != a)) a = undefined;
while (++i < n) if ((b = f.call(array, array[i], i)) != null && b > a) a = b;
}
return a;
};
Then it would just be d3.max(d3.max1(a)).