print every nth line into a row using gawk

Question

I have a very huge file in which I need to obtain every nth line and print it into a row.

My data:

1      937  4.320194
2      667  4.913314
3      9         


        

Answer 1

Doing it directly in command Prompt (Windows).

Put the gawk.exe file in the folder where the file is and start a command Prompt in the folder, and write

gawk "NR%n==x" oldfile.txt>newfile.txt

n is every n'th line you want to print and x is the starting line.

E.g n=10 and x=1, printing line 1,11,21,31,41......end line from the original file into the new file.

E.g n=20 and x=5, printing line 5,25,45,65......end line from the original file into the new file.