print every nth line into a row using gawk

Question

I have a very huge file in which I need to obtain every nth line and print it into a row.

My data:

1      937  4.320194
2      667  4.913314
3      9         


        

Answer 1

To print every second line, starting with the first:

awk 'NR%2==1' file.txt

To print every tenth line, starting with the tenth line:

awk 'NR%10==0' file.txt

---

To use this in a script, add the following to a file called script.awk:

BEGIN {
    print "Processing file"
}

NR%10==0

END {
    print "Finished processing"
}

Then execute:

awk -f script.awk file.txt