How do I get the last word in each line with bash

Question

For example i have a file:

$ cat file

i am the first example.

i am the second line.

i do a question about a file.

and i need:

Answer 1

tldr;

$ awk '{print $NF}' file.txt | paste -sd, | sed 's/,/, /g'

For a file like this

$ cat file.txt
The quick brown fox
jumps over
the lazy dog.

the given command will print

fox, over, dog.

How it works:

• awk '{print $NF}' : prints the last field of every line
• paste -sd, : reads stdin serially (-s, one file at a time) and writes fields comma-delimited (-d,)
• sed 's/,/, /g' : substitutes "," with ", " globally (for all instances)

References:

• https://linux.die.net/man/1/awk
• https://linux.die.net/man/1/paste
• https://linux.die.net/man/1/sed