C++ lambda with captures as a function pointer

Question

I was playing with C++ lambdas and their implicit conversion to function pointers. My starting example was using them as callback for the ftw function. This works as expecte

Answer 1

My solution, just use a function pointer to refer to a static lambda.

typedef int (* MYPROC)(int);

void fun(MYPROC m)
{
    cout << m(100) << endl;
}

template
void fun2(T f)
{
    cout << f(100) << endl;
}

void useLambdaAsFunPtr()
{
    int p = 7;
    auto f = [p](int a)->int {return a * p; };

    //fun(f);//error
    fun2(f);
}

void useLambdaAsFunPtr2()
{
    int p = 7;
    static auto f = [p](int a)->int {return a * p; };
    MYPROC ff = [](int i)->int { return f(i); };
    //here, it works!
    fun(ff);
}

void test()
{
    useLambdaAsFunPtr2();
}