Java ByteBuffer to String

Question

Is this a correct approach to convert ByteBuffer to String in this way,

String k = \"abcd\";
ByteBuffer b = ByteBuffer.wrap(k.getBytes());
String v = new Str         


        

Answer 1

Convert a String to ByteBuffer, then from ByteBuffer back to String using Java:

import java.nio.charset.Charset;
import java.nio.*;

String babel = "obufscate thdé alphebat and yolo!!";
System.out.println(babel);
//Convert string to ByteBuffer:
ByteBuffer babb = Charset.forName("UTF-8").encode(babel);
try{
    //Convert ByteBuffer to String
    System.out.println(new String(babb.array(), "UTF-8"));
}
catch(Exception e){
    e.printStackTrace();
}

Which prints the printed bare string first, and then the ByteBuffer casted to array():

obufscate thdé alphebat and yolo!!
obufscate thdé alphebat and yolo!!

Also this was helpful for me, reducing the string to primitive bytes can help inspect what's going on:

String text = "こんにちは";
//convert utf8 text to a byte array
byte[] array = text.getBytes("UTF-8");
//convert the byte array back to a string as UTF-8
String s = new String(array, Charset.forName("UTF-8"));
System.out.println(s);
//forcing strings encoded as UTF-8 as an incorrect encoding like
//say ISO-8859-1 causes strange and undefined behavior
String sISO = new String(array, Charset.forName("ISO-8859-1"));
System.out.println(sISO);

Prints your string interpreted as UTF-8, and then again as ISO-8859-1:

こんにちは
ããã«ã¡ã¯