C# constructor execution order

Question

In C#, when you do

Class(Type param1, Type param2) : base(param1) 

is the constructor of the class executed first, and then the superclass

Answer 1

Not sure if this should be a comment/answer but for those who learn by example this fiddle illustrates the order as well: https://dotnetfiddle.net/kETPKP

using System;

// order is approximately
/*
   1) most derived initializers first.
   2) most base constructors first (or top-level in constructor-stack first.)
*/
public class Program
{
    public static void Main()
    {
        var d = new D();
    }
}

public class A
{
    public readonly C ac = new C("A");

    public A()
    {
        Console.WriteLine("A");
    }
    public A(string x) : this()
    {
        Console.WriteLine("A got " + x);
    }
}

public class B : A
{
    public readonly C bc = new C("B");

    public B(): base()
    {
        Console.WriteLine("B");
    }
    public B(string x): base(x)
    {
        Console.WriteLine("B got " + x);
    }
}

public class D : B
{
    public readonly C dc = new C("D");

    public D(): this("ha")
    {
        Console.WriteLine("D");
    }
    public D(string x) : base(x)
    {
        Console.WriteLine("D got " + x);
    }
}

public class C
{
    public C(string caller)
    {
        Console.WriteLine(caller + "'s C.");
    }
}

Result:

D's C.
B's C.
A's C.
A
A got ha
B got ha
D got ha
D