Convert digits into words with JavaScript

Question

I am making a code which converts the given amount into words, heres is what I have got after googling. But I think its a little lengthy code to achieve a simple task. Two R

Answer 1

I modified @McShaman's code, converted it to CoffeeScript, and added docs via JSNice. Here's the result, for those interested (English):

###
    Convert an integer to an English string equivalent
    @param {Integer} number the integer to be converted
    @return {String} the English number equivalent
###
inWords = (number) ->
    ###
        @property {Array}
    ###
    englishIntegers = [
        ""
        "one "
        "two "
        "three "
        "four "
        "five "
        "six "
        "seven "
        "eight "
        "nine "
        "ten "
        "eleven "
        "twelve "
        "thirteen "
        "fourteen "
        "fifteen "
        "sixteen "
        "seventeen "
        "eighteen "
        "nineteen "
    ]

    ###
        @property {Array}
    ###
    englishIntegerTens = [
        ""
        ""
        "twenty"
        "thirty"
        "forty"
        "fifty"
        "sixty"
        "seventy"
        "eighty"
        "ninety"
    ]

    ###
        @property {Array}
    ###
    englishIntegerThousands = [
        "thousand"
        "million"
        ""
    ]
    number = number.toString()
    return "" if number.length > 9

    ###
        @property {string}
    ###
    number = ("000000000" + number).substr(-9)

    ###
      @property {(Array.|null)}
      ###
    number = number.match(/.{3}/g)

    ###
        @property {string}
    ###
    convertedWords = ""

    ###
        @property {number}
    ###
    i = 0
    while i < englishIntegerThousands.length

        ###
            @property {string}
        ###
        currentNumber = number[i]

        ###
            @property {string}
        ###
        tempResult = ""
        tempResult += (if convertedWords isnt "" then " " + englishIntegerThousands[i] + " " else "")
        tempResult += (if currentNumber[0] isnt 0 then englishIntegers[Number(currentNumber[0])] + "hundred " else "")

        ###
            @property {string}
        ###
        currentNumber = currentNumber.substr(1)
        tempResult += (if currentNumber isnt 0 then ((if tempResult isnt "" then "and " else "")) + (englishIntegers[Number(currentNumber)] or englishIntegerTens[currentNumber[0]] + " " + englishIntegers[currentNumber[1]]) else "")
        convertedWords += tempResult
        i++
    convertedWords