How to redirect to previous page in Django after POST request

Question

I face a problem which I can\'t find a solution for. I have a button in navbar which is available on all pages and it is a button responsible for creating some content.

Answer 1

My favorite way to do that is giving the request.path as GET parameter to the form. It will pass it when posting until you redirect. In Class-Based-Views (FormView, UpdateView, DeleteView or CreateView) you can directly use it as success_url. Somewhere i read that it's bad practise to mix GET and POST but the simplicity of this makes it to an exception for me.

---

Example urls.py:

urlpatterns = [
    path('', HomeView.as_view(), name='home'),
    path('user/update/', UserUpdateView.as_view(), name='user_update'),
]

Link to the form inside of the template:

Update User

Class-Based-View:

class UserUpdateView(UpdateView):
    ...
    def get_success_url(self):
        return self.request.GET.get('next', reverse('home'))

---

In your function based view you can use it as follows:

def createadv(request):
    uw = getuw(request.user.username)
    if request.method =='POST':
        form = AdverForm(request.POST, request.FILES)
        if form.is_valid():
            form.instance.user = request.user
            form.save()
            next = request.GET.get('next', reverse('home'))
            return HttpResponseRedirect(next)

    args = {}
    args.update(csrf(request))
    args['username'] = request.user.username
    args['form'] = AdverForm()
    args['uw'] = uw
    return  render_to_response('createadv.html', args)