How can I pass a member function where a free function is expected?

Question

The question is the following: consider this piece of code:

#include 


class aClass
{
public:
    void aTest(int a, int b)
    {
        prin         


        

Answer 1

Not sure why this incredibly simple solution has been passed up:

#include 

class aClass
{
public:
    void aTest(int a, int b)
    {
        printf("%d + %d = %d\n", a, b, a + b);
    }
};

template
void function1(void (C::*function)(int, int), C& c)
{
    (c.*function)(1, 1);
}
void function1(void (*function)(int, int)) {
  function(1, 1);
}

void test(int a,int b)
{
    printf("%d - %d = %d\n", a , b , a - b);
}

int main (int argc, const char* argv[])
{
    aClass a;

    function1(&test);
    function1(&aClass::aTest, a);
    return 0;
}

Output:

1 - 1 = 0
1 + 1 = 2