Parfor for Python

Question

I am looking for a definitive answer to MATLAB\'s parfor for Python (Scipy, Numpy).

Is there a solution similar to parfor? If not, what is the complication for creat

Answer 1

I tried all solutions here, but found that the simplest way and closest equivalent to matlabs parfor is numba's prange.

Essentially you change a single letter in your loop, range to prange:

from numba import autojit, prange

@autojit
def parallel_sum(A):
    sum = 0.0
    for i in prange(A.shape[0]):
        sum += A[i]

    return sum