Parfor for Python

Question

I am looking for a definitive answer to MATLAB\'s parfor for Python (Scipy, Numpy).

Is there a solution similar to parfor? If not, what is the complication for creat

Answer 1

Jupyter Notebook

To see an example consider you want to write the equivalence of this Matlab code on in Python

matlabpool open 4
parfor n=0:9
   for i=1:10000
       for j=1:10000
           s=j*i   
       end
   end
   n
end
disp('done')

The way one may write this in python particularly in jupyter notebook. You have to create a function in the working directory (I called it FunForParFor.py) which has the following

def func(n):
    for i in range(10000):
        for j in range(10000):
            s=j*i
    print(n)

Then I go to my Jupyter notebook and write the following code

import multiprocessing  
import FunForParFor

if __name__ == '__main__':
    pool = multiprocessing.Pool(processes=4)
    pool.map(FunForParFor.func, range(10))
    pool.close()
    pool.join()   
    print('done')

This has worked for me! I just wanted to share it here to give you a particular example.