Pass multiple parameters to concurrent.futures.Executor.map?

Question

The concurrent.futures.Executor.map takes a variable number of iterables from which the function given is called. How should I call it if I have a generator that pro

Answer 1

You need to remove the * on the map call:

args = ((a, b) for b in c)
for result in executor.map(f, args):
    pass

This will call f, len(args) times, where f should accept one parameter.

If you want f to accept two parameters you can use a lambda call like:

args = ((a, b) for b in c)
for result in executor.map(lambda p: f(*p), args):   # (*p) does the unpacking part
    pass