Creating a (ES6) promise without starting to resolve it

Question

Using ES6 promises, how do I create a promise without defining the logic for resolving it? Here\'s a basic example (some TypeScript):

Answer 1

Things are slowly getting better in JavaScript land, but this is one case where things are still unnecessarily complicated. Here's a simple helper to expose the resolve and reject functions:

Promise.unwrapped = () => {
  let resolve, reject, promise = new Promise((_resolve, _reject) => {
    resolve = _resolve, reject = _reject
  })
  promise.resolve = resolve, promise.reject = reject
  return promise
}

// a contrived example

let p = Promise.unwrapped()
p.then(v => alert(v))
p.resolve('test')

Apparently there used to be a Promise.defer helper, but even that insisted on the deferred object being separate from the promise itself...