Two Dimensional Array Implementation Using Double Pointer

Question

Please consider the following code:

#include 
#include 

#define NUM_ARRAYS     4
#define NUM_ELEMENTS   4
#define INVALID_VAL         


        

Answer 1

*ptr + 1 is address of ptr[0][1]

Because, we know

ptr[0][1] == *(*(ptr+0)+1)

Now putting ampersand on both side

&ptr[0][1] == &*(*(ptr+0)+1)

You know that ampersand with asterisk is like plus sign with minus sign? They get cancelled. So this becomes

&ptr[0][1] == (*(ptr+0)+1)

Which is same as

&ptr[0][1] == *(ptr+0)+1

Which is again same as

&ptr[0][1] == *ptr+1

This is my first statement.