jQuery return ajax result into outside variable

Question

I have some problem using ajax.

How can I assign all result from ajax into outside variable ?

I google it up and found this code..

var return         


        

Answer 1

I solved it by doing like that:

var return_first = (function () {
        var tmp = $.ajax({
            'type': "POST",
            'dataType': 'html',
            'url': "ajax.php?first",
            'data': { 'request': "", 'target': arrange_url, 'method': 
                    method_target },
            'success': function (data) {
                tmp = data;
            }
        }).done(function(data){
                return data;
        });
      return tmp;
    });

• Be careful 'async':fale javascript will be asynchronous.