jQuery return ajax result into outside variable

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栀梦
栀梦 2020-12-07 16:53

I have some problem using ajax.

How can I assign all result from ajax into outside variable ?

I google it up and found this code..

var return         


        
6条回答
  •  隐瞒了意图╮
    2020-12-07 17:10

    This is all you need to do:

    var myVariable;
    
    $.ajax({
        'async': false,
        'type': "POST",
        'global': false,
        'dataType': 'html',
        'url': "ajax.php?first",
        'data': { 'request': "", 'target': 'arrange_url', 'method': 'method_target' },
        'success': function (data) {
            myVariable = data;
        }
    });
    

    NOTE: Use of "async" has been depreciated. See https://xhr.spec.whatwg.org/.

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