How to define a function inside another function in Bash?

Question

I have the following code

func1(){
    #some function thing
    function2(){
        #second function thing
    }
}

and I want to call

Answer 1

Your code should work as written provided you only call the nested function after it's defined.

As said in another answer, a func(){<...>} statement is an executable statement that defines a name (in the global scope) associated with the function. Just like if you defined a variable.

So, you can use func2 anywhere in the code after the func2(){<...>} statement has run:

#func2 not defined
func1(){
    #not defined
    func2(){<...>}
    #defined
}
#not defined
func1
#defined
func3(){
    #only defined if func3 is called after `func2(){<...>}' has run
}