How do I create an array of strings in C?

Question

I am trying to create an array of strings in C. If I use this code:

char (*a[2])[14];
a[0]=\"blah\";
a[1]=\"hmm\";

gcc gives me \"warning:

Answer 1

I was missing somehow more dynamic array of strings, where amount of strings could be varied depending on run-time selection, but otherwise strings should be fixed.

I've ended up of coding code snippet like this:

#define INIT_STRING_ARRAY(...)          \
    {                                   \
        char* args[] = __VA_ARGS__;     \
        ev = args;                      \
        count = _countof(args);         \
    }

void InitEnumIfAny(String& key, CMFCPropertyGridProperty* item)
{
    USES_CONVERSION;
    char** ev = nullptr;
    int count = 0;

    if( key.Compare("horizontal_alignment") )
        INIT_STRING_ARRAY( { "top", "bottom" } )

    if (key.Compare("boolean"))
        INIT_STRING_ARRAY( { "yes", "no" } )

    if( ev == nullptr )
        return;

    for( int i = 0; i < count; i++)
        item->AddOption(A2T(ev[i]));

    item->AllowEdit(FALSE);
}

char** ev picks up pointer to array strings, and count picks up amount of strings using _countof function. (Similar to sizeof(arr) / sizeof(arr[0])).

And there is extra Ansi to unicode conversion using A2T macro, but that might be optional for your case.