Why does !!1==“1” equal true and !!2==“2” equal false?

Question

As the title states, why does:

> !!1==\"1\"

equal

True

and

> !!2==\"2\"
         


        

Answer 1

Its a precedence operator problem.

The ! operator is an unary operator. That means the left side must be an expression or a boolean evaluable section. See Javascript MDN.

!!1==1 is not necessary !!(1==1)
!!2==2 is not necessary !!(2==2)

I think that these expressions should be consistent if the equal operator has more precedence than ! operator. But if we consider the opposite, evaluating first negations we have:

!!1 == 1
!1 -> false
!!1 -> true
!!1 == 1 

And with the two

!!2==2
!2 -> false
!!2 -> true
(!!2) == 2 -> false

That is because the ! operator has precedence over == operator

See Mozilla Operator Preference