Non const lvalue references

Question

Why can you do this

int a;
const double &m = a;

But when you do this

int a;
double &m = a;

you ge

Answer 1

Because making modification on a temporary is meaningless, c++ don't want you to bind non-const reference to a temporary. For example.

int a;
double &m = a;  // caution:this does not work.

What if it works? a is of type int and is being converted to double. So a temporary is created.

You can modify m, which is bound to a temporary, but almost nothing happens.After the modification, variable a does not change(what's worse, you might think a has changed, which may cause problems).