Python 3 sort a dict by its values

Question

The only methods I found work for python2 or return only list of tuples.

Is it possible to sort dictionary, e.g. {\"aa\": 3, \"bb\": 4, \"cc\": 2, \"dd\": 1}

Answer 1

To sort dictionary, we could make use of operator module. Here is the operator module documentation.

import operator                             #Importing operator module
dc =  {"aa": 3, "bb": 4, "cc": 2, "dd": 1}  #Dictionary to be sorted

dc_sort = sorted(dc.items(),key = operator.itemgetter(1),reverse = True)
print dc_sort

Output sequence will be a sorted list :

[('bb', 4), ('aa', 3), ('cc', 2), ('dd', 1)]

If we want to sort with respect to keys, we can make use of

dc_sort = sorted(dc.items(),key = operator.itemgetter(0),reverse = True)

Output sequence will be :

[('dd', 1), ('cc', 2), ('bb', 4), ('aa', 3)]