Python 3 sort a dict by its values

Question

The only methods I found work for python2 or return only list of tuples.

Is it possible to sort dictionary, e.g. {\"aa\": 3, \"bb\": 4, \"cc\": 2, \"dd\": 1}

Answer 1

You can sort by values in reverse order (largest to smallest) using a dictionary comprehension:

{k: d[k] for k in sorted(d, key=d.get, reverse=True)}
# {'b': 4, 'a': 3, 'c': 2, 'd': 1}

If you want to sort by values in ascending order (smallest to largest)

{k: d[k] for k in sorted(d, key=d.get)}
# {'d': 1, 'c': 2, 'a': 3, 'b': 4}

If you want to sort by the keys in ascending order

{k: d[k] for k in sorted(d)}
# {'a': 3, 'b': 4, 'c': 2, 'd': 1}

This works on CPython 3.6+ and any implementation of Python 3.7+ because dictionaries keep insertion order.