How can I use a variable as a variable name in Perl?

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离开以前
离开以前 2020-11-22 14:48

I need to achieve the following in perl

printmsg(@val1, $msg1) if @val1;
printmsg(@val2, $msg2) if @val2;
printmsg(@val3, $msg3) if @val3;
printmsg(@val4, $m         


        
3条回答
  •  轮回少年
    2020-11-22 15:06

    Whenever you find yourself postfixing variable names with an integer index, realize that you should have used an array instead:

    my @msgs = ('msg1', 'msg2', ..., 'msg6');
    my @vals = ( [ @val1 ], [ @val2 ], ..., [ @val6 ] );
    

    See also the FAQ How can I use a variable as a variable name?

    As the answer to the FAQ notes, if the variables are not indexed by an integer, you can use a hash table:

    By using symbolic references, you are just using the package's symbol-table hash (like %main::) instead of a user-defined hash. The solution is to use your own hash or a real reference instead.

    $USER_VARS{"fred"} = 23;
    my $varname = "fred";
    $USER_VARS{$varname}++;  # not $$varname++
    

    You should read the entire FAQ list at least once a year.

    Update: I purposefully left symbolic references out of my answer because they are unnecessary and likely very harmful in the context of your question. For more information, see Why it's stupid to 'use a variable as a variable name'?, part 2 and part 3 by mjd.

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