Ignore percent sign in batch file

Question

I have a batch file which moves files from one folder to another. The batch file is generated by another process.

Some of the files I need to move have the string \"

Answer 1

You need to use %% in this case. Normally using a ^ (caret) would work, but for % signs you need to double up.

In the case of %%1 or %%i or echo.%%~dp1, because % indicates input either from a command or from a variable (when surrounded with %; %variable%)

To achieve what you need:

move /y "\\myserver\myfolder\file%%20name.txt" "\\myserver\otherfolder"

I hope this helps!