Ignore percent sign in batch file

Question

I have a batch file which moves files from one folder to another. The batch file is generated by another process.

Some of the files I need to move have the string \"

Answer 1

You should be able to use a caret (^) to escape a percent sign.

^{Editor's note: The link is dead now; either way: It is % itself that escapes %, but only in batch files, not at the command prompt; ^ never escapes %, but at the command prompt it can be used indirectly to prevent variable expansion, in unquoted strings only.}

The reason %2 is disappearing is that the batch file is substituting the second argument passed in, and your seem to not have a second argument. One way to work around that would be to actually try foo.bat ^%1 ^%2... so that when a %2 is encountered in a command, it is actually substituted with a literal %2.