Python Pandas : pivot table with aggfunc = count unique distinct

Question

df2 = pd.DataFrame({\'X\' : [\'X1\', \'X1\', \'X1\', \'X1\'], \'Y\' : [\'Y2\',\'Y1\',\'Y1\',\'Y1\'], \'Z\' : [\'Z3\',\'Z1\',\'Z1\',\'Z2\']})

    X   Y   Z
0  X1  Y2         


        

Answer 1

aggfunc=pd.Series.nunique provides distinct count.

Full Code:

df2.pivot_table(values='X', rows='Y', cols='Z', 
                         aggfunc=pd.Series.nunique)

Credit to @hume for this solution (see comment under the accepted answer). Adding as an answer here for better discoverability.