Iterate over all pairs of consecutive items in a list [duplicate]

Answer 1

If you wanted something inline but not terribly readable here's another solution that makes use of generators. I expect it's also not the best performance wise :-/

Convert list into generator with a tweak to end before the last item:

gen = (x for x in l[:-1])

Convert it into pairs:

[(gen.next(), x) for x in l[1:]]

That's all you need.