Function pointer as parameter

Question

I try to call a function which passed as function pointer with no argument, but I can\'t make it work.

void *disconnectFunc;

void D::setDisconnectFunc(void          


        

Answer 1

Replace void *disconnectFunc; with void (*disconnectFunc)(); to declare function pointer type variable. Or even better use a typedef:

typedef void (*func_t)(); // pointer to function with no args and void return
...
func_t fptr; // variable of pointer to function
...
void D::setDisconnectFunc( func_t func )
{
    fptr = func;
}

void D::disconnected()
{
    fptr();
    connected = false;
}