The order of keys in dictionaries

Question

Code:

d = {\'a\': 0, \'b\': 1, \'c\': 2}
l = d.keys()

print l

This prints [\'a\', \'c\', \'b\']. I\'m unsure of how the metho

Answer 1

Although the order does not matter as the dictionary is hashmap. It depends on the order how it is pushed in:

s = 'abbc'
a = 'cbab'

def load_dict(s):
    dict_tmp = {}
    for ch in s:
        if ch in dict_tmp.keys():
            dict_tmp[ch]+=1
        else:
            dict_tmp[ch] = 1
    return dict_tmp

dict_a = load_dict(a)
dict_s = load_dict(s)
print('for string %s, the keys are %s'%(s, dict_s.keys()))
print('for string %s, the keys are %s'%(a, dict_a.keys()))

output:
for string abbc, the keys are dict_keys(['a', 'b', 'c'])
for string cbab, the keys are dict_keys(['c', 'b', 'a'])