RFC 1123 Date Representation in Python?

前端 未结 5 1345
南笙
南笙 2020-12-07 12:28

Is there a fairly easy way to convert a datetime object into an RFC 1123 (HTTP/1.1) date/time string, i.e. a string with the format

Sun, 06 Nov 1994 08:49:37         


        
5条回答
  •  陌清茗
    陌清茗 (楼主)
    2020-12-07 12:32

    You can use wsgiref.handlers.format_date_time from the stdlib which does not rely on locale settings

    from wsgiref.handlers import format_date_time
    from datetime import datetime
    from time import mktime
    
    now = datetime.now()
    stamp = mktime(now.timetuple())
    print format_date_time(stamp) #--> Wed, 22 Oct 2008 10:52:40 GMT
    

    You can use email.utils.formatdate from the stdlib which does not rely on locale settings

    from email.utils import formatdate
    from datetime import datetime
    from time import mktime
    
    now = datetime.now()
    stamp = mktime(now.timetuple())
    print formatdate(
        timeval     = stamp,
        localtime   = False,
        usegmt      = True
    ) #--> Wed, 22 Oct 2008 10:55:46 GMT
    

    If you can set the locale process wide then you can do:

    import locale, datetime
    
    locale.setlocale(locale.LC_TIME, 'en_US')
    datetime.datetime.utcnow().strftime('%a, %d %b %Y %H:%M:%S GMT')
    

    If you don't want to set the locale process wide you could use Babel date formating

    from datetime import datetime
    from babel.dates import format_datetime
    
    now = datetime.utcnow()
    format = 'EEE, dd LLL yyyy hh:mm:ss'
    print format_datetime(now, format, locale='en') + ' GMT'
    

    A manual way to format it which is identical with wsgiref.handlers.format_date_time is:

    def httpdate(dt):
        """Return a string representation of a date according to RFC 1123
        (HTTP/1.1).
    
        The supplied date must be in UTC.
    
        """
        weekday = ["Mon", "Tue", "Wed", "Thu", "Fri", "Sat", "Sun"][dt.weekday()]
        month = ["Jan", "Feb", "Mar", "Apr", "May", "Jun", "Jul", "Aug", "Sep",
                 "Oct", "Nov", "Dec"][dt.month - 1]
        return "%s, %02d %s %04d %02d:%02d:%02d GMT" % (weekday, dt.day, month,
            dt.year, dt.hour, dt.minute, dt.second)
    

提交回复
热议问题