Difference between fmt.Println() and println() in Go

Question

As illustrated below, both fmt.Println() and println() give same output in Go: Hello world!

But: how do they differ from each

Answer 1

I can see difference here:

rangeOverIntsAndStrings(1, 5)

func rangeOverIntsAndStrings(args ...interface{}) {
    for _, v := range args {
        println(v)
    }
}

// output

(0x108f060,0x10c5358)
(0x108f060,0x10c5360)

vs

func rangeOverIntsAndStrings(args ...interface{}) {
    for _, v := range args {
        fmt.Println(v)
    }
}

// output

1
5