Note: This is asking for the reverse of the usual tuple-to-array conversion.
I have to pass an argument to a (wrapped c++) function as a nested tupl
If you like long cuts, here is another way tuple(tuple(a_m.tolist()) for a_m in a )
from numpy import array
a = array([[1, 2],
[3, 4]])
tuple(tuple(a_m.tolist()) for a_m in a )
The output is ((1, 2), (3, 4))
Note just (tuple(a_m.tolist()) for a_m in a ) will give a generator expresssion. Sort of inspired by @norok2's comment to Greg von Winckel's answer