C/C++ Why to use unsigned char for binary data?

Question

Is it really necessary to use unsigned char to hold binary data as in some libraries which work on character encoding or binary buffers? To make sense of my que

Answer 1

Bytes are usually intended as unsigned 8 bit wide integers.

Now, char doesn't specify the sign of the integer: on some compilers char could be signed, on other it may be unsigned.

If I add a bit shift operation to the code you wrote, then I will have an undefined behaviour. The added comparison will also have an unexpected result.

char c[5], d[5];
c[0] = 0xF0;
c[1] = 0xA4;
c[2] = 0xAD;
c[3] = 0xA2;
c[4] = '\0';
c[0] >>= 1; // If char is signed, will the 7th bit go to 0 or stay the same?

bool isBiggerThan0 = c[0] > 0; // FALSE if char is signed!

printf("%s\n", c);
memcpy(d, c, 5);
printf("%s\n", d);

Regarding the warning during the compilation: if the char is signed then you are trying to assign the value 0xf0, which cannot be represented in the signed char (range -128 to +127), so it will be casted to a signed value (-16).

Declaring the char as unsigned will remove the warning, and is always good to have a clean build without any warning.