Set Django IntegerField by choices=… name

Question

When you have a model field with a choices option you tend to have some magic values associated with human readable names. Is there in Django a convenient way to set these f

Answer 1

class Sequence(object):
    def __init__(self, func, *opts):
        keys = func(len(opts))
        self.attrs = dict(zip([t[0] for t in opts], keys))
        self.choices = zip(keys, [t[1] for t in opts])
        self.labels = dict(self.choices)
    def __getattr__(self, a):
        return self.attrs[a]
    def __getitem__(self, k):
        return self.labels[k]
    def __len__(self):
        return len(self.choices)
    def __iter__(self):
        return iter(self.choices)
    def __deepcopy__(self, memo):
        return self

class Enum(Sequence):
    def __init__(self, *opts):
        return super(Enum, self).__init__(range, *opts)

class Flags(Sequence):
    def __init__(self, *opts):
        return super(Flags, self).__init__(lambda l: [1<

Use it like this:

Priorities = Enum(
    ('LOW', 'Low'),
    ('NORMAL', 'Normal'),
    ('HIGH', 'High')
)

priority = models.IntegerField(default=Priorities.LOW, choices=Priorities)