Swipe ListView item From right to left show delete button

Question

I have a custom ListView showing the list of words selecting from database. When I swipe this listview item i want to show Delete button like image below. And when I press t

Answer 1

Define a ViewPager in your layout .xml:

And then, in your activity / fragment, set a custom pager adapter:

In an activity:

protected void onCreate(Bundle savedInstanceState) {
    PagerAdapter adapter = new PagerAdapter(getSupportFragmentManager());
    ViewPager pager = (ViewPager) findViewById(R.id.example_pager);

    pager.setAdapter(adapter);
    // pager.setOnPageChangeListener(this); // You can set a page listener here
    pager.setCurrentItem(0);
}

In a fragment:

public View onCreateView(LayoutInflater inflater, ViewGroup container, Bundle savedInstanceState) {
    View view = inflater.inflate(R.layout.fragment_layout, container, false);

    if (view != null) {
        PagerAdapter adapter = new PagerAdapter(getSupportFragmentManager());
        ViewPager pager = (ViewPager) view.findViewById(R.id.example_pager);

        pager.setAdapter(adapter);
        // pager.setOnPageChangeListener(this); // You can set a page listener here
        pager.setCurrentItem(0);
    }

    return view;
}

Create our custom pager class:

// setup your PagerAdapter which extends FragmentPagerAdapter
class PagerAdapter extends FragmentPagerAdapter {
    public static final int NUM_PAGES = 2;
    private CustomFragment[] mFragments = new CustomFragment[NUM_PAGES];
    public PagerAdapter(FragmentManager fragmentManager) {
        super(fragmentManager);
    }
    @ Override
    public int getCount() {
        return NUM_PAGES;
    }
    @ Override
    public Fragment getItem(int position) {
        if (mFragments[position] == null) {
               // this calls the newInstance from when you setup the ListFragment
            mFragments[position] = new CustomFragment();
        }
        return mFragments[position];
    }
}