How does the template parameter of std::function work? (implementation)

Question

In Bjarne Stroustrup\'s home page (C++11 FAQ):

struct X { int foo(int); };

std::function f;
f = &X::foo; //pointer to membe         


        

Answer 1

They're not function pointers. That's what std::function exists for. It wraps whatever callable types you give it. You should check out boost::bind- it's often used to make member function pointers callable as (this, args).