This question is the direct analogon to Class type check with TypeScript
I need to find out at runtime if a variable of type any implements an interface. Here\'s my
How about User-Defined Type Guards? https://www.typescriptlang.org/docs/handbook/advanced-types.html
interface Bird {
fly();
layEggs();
}
interface Fish {
swim();
layEggs();
}
function isFish(pet: Fish | Bird): pet is Fish { //magic happens here
return (pet).swim !== undefined;
}
// Both calls to 'swim' and 'fly' are now okay.
if (isFish(pet)) {
pet.swim();
}
else {
pet.fly();
}