I\'m writing a bit of code to display a bar (or line) graph in our software. Everything\'s going fine. The thing that\'s got me stumped is labeling the Y axis.
The
The answer by Toon Krijthe does work most of the time. But sometimes it will produce excess number of ticks. It won't work with negative numbers as well. The overal approach to the problem is ok but there is a better way to handle this. The algorithm you want to use will depend on what you really want to get. Below I'm presenting you my code which I used in my JS Ploting library. I've tested it and it always works (hopefully ;) ). Here are the major steps:
Lets start. First the basic calculations
var range = Math.abs(xMax - xMin); //both can be negative
var rangeOrder = Math.floor(Math.log10(range)) - 1;
var power10 = Math.pow(10, rangeOrder);
var maxRound = (xMax > 0) ? Math.ceil(xMax / power10) : Math.floor(xMax / power10);
var minRound = (xMin < 0) ? Math.floor(xMin / power10) : Math.ceil(xMin / power10);
I round minimum and maximum values to be 100% sure that my plot will cover all the data. It is also very important to floor log10 of range wheter or not it is negative and substract 1 later. Otherwise your algorithm won't work for numbers that are lesser than one.
var fullRange = Math.abs(maxRound - minRound);
var tickSize = Math.ceil(fullRange / (this.XTickCount - 1));
//You can set nice looking ticks if you want
//You can find exemplary method below
tickSize = this.NiceLookingTick(tickSize);
//Here you can write a method to determine if you need zero tick
//You can find exemplary method below
var isZeroNeeded = this.HasZeroTick(maxRound, minRound, tickSize);
I use "nice looking ticks" to avoid ticks like 7, 13, 17 etc. Method I use here is pretty simple. It is also nice to have zeroTick when needed. Plot looks much more professional this way. You will find all the methods at the end of this answer.
Now you have to calculate upper and lower bounds. This is very easy with zero tick but requires a little bit more effort in other case. Why? Because we want to center the plot within upper and lower bound nicely. Have a look at my code. Some of the variables are defined outside of this scope and some of them are properties of an object in which whole presented code is kept.
if (isZeroNeeded) {
var positiveTicksCount = 0;
var negativeTickCount = 0;
if (maxRound != 0) {
positiveTicksCount = Math.ceil(maxRound / tickSize);
XUpperBound = tickSize * positiveTicksCount * power10;
}
if (minRound != 0) {
negativeTickCount = Math.floor(minRound / tickSize);
XLowerBound = tickSize * negativeTickCount * power10;
}
XTickRange = tickSize * power10;
this.XTickCount = positiveTicksCount - negativeTickCount + 1;
}
else {
var delta = (tickSize * (this.XTickCount - 1) - fullRange) / 2.0;
if (delta % 1 == 0) {
XUpperBound = maxRound + delta;
XLowerBound = minRound - delta;
}
else {
XUpperBound = maxRound + Math.ceil(delta);
XLowerBound = minRound - Math.floor(delta);
}
XTickRange = tickSize * power10;
XUpperBound = XUpperBound * power10;
XLowerBound = XLowerBound * power10;
}
And here are methods I mentioned before which you can write by yourself but you can also use mine
this.NiceLookingTick = function (tickSize) {
var NiceArray = [1, 2, 2.5, 3, 4, 5, 10];
var tickOrder = Math.floor(Math.log10(tickSize));
var power10 = Math.pow(10, tickOrder);
tickSize = tickSize / power10;
var niceTick;
var minDistance = 10;
var index = 0;
for (var i = 0; i < NiceArray.length; i++) {
var dist = Math.abs(NiceArray[i] - tickSize);
if (dist < minDistance) {
minDistance = dist;
index = i;
}
}
return NiceArray[index] * power10;
}
this.HasZeroTick = function (maxRound, minRound, tickSize) {
if (maxRound * minRound < 0)
{
return true;
}
else if (Math.abs(maxRound) < tickSize || Math.round(minRound) < tickSize) {
return true;
}
else {
return false;
}
}
There is only one more thing that is not included here. This is the "nice looking bounds". These are lower bounds that are numbers similar to the numbers in "nice looking ticks". For example it is better to have the lower bound starting at 5 with tick size 5 than having a plot that starts at 6 with the same tick size. But this my fired I leave it to you.
Hope it helps. Cheers!