Reusing output from last command in Bash

Question

Is the output of a Bash command stored in any register? E.g. something similar to $? capturing the output instead of the exit status.

I could assign the

Answer 1

One way of doing that is by using trap DEBUG:

f() { bash -c "$BASH_COMMAND" >& /tmp/out.log; }
trap 'f' DEBUG

Now most recently executed command's stdout and stderr will be available in /tmp/out.log

Only downside is that it will execute a command twice: once to redirect output and error to /tmp/out.log and once normally. Probably there is some way to prevent this behavior as well.