Generate random password string with requirements in javascript

Question

I want to generate a random string that has to have 5 letters from a-z and 3 numbers.

How can I do this with JavaScript?

I\'ve got the following script, but

Answer 1

For someone who is looking for a simplest script. No while (true), no if/else, no declaration.

Base on mwag's answer, but this one uses crypto.getRandomValues, a stronger random than Math.random.

Array(20)
  .fill('0123456789ABCDEFGHIJKLMNOPQRSTUVWXYZabcdefghijklmnopqrstuvwxyz~!@-#$')
  .map(x => x[Math.floor(crypto.getRandomValues(new Uint32Array(1))[0] / (0xffffffff + 1) * x.length)])
  .join('');

See this for 0xffffffff.

Alternative 1

var generatePassword = (
  length = 20,
  wishlist = "0123456789ABCDEFGHIJKLMNOPQRSTUVWXYZabcdefghijklmnopqrstuvwxyz~!@-#$"
) => Array(length)
      .fill('')
      .map(() => wishlist[Math.floor(crypto.getRandomValues(new Uint32Array(1))[0] / (0xffffffff + 1) * wishlist.length)])
      .join('');

console.log(generatePassword());

Alternative 2

var generatePassword = (
  length = 20,
  wishlist = '0123456789ABCDEFGHIJKLMNOPQRSTUVWXYZabcdefghijklmnopqrstuvwxyz~!@-#$'
) =>
  Array.from(crypto.getRandomValues(new Uint32Array(length)))
    .map((x) => wishlist[x % wishlist.length])
    .join('')

console.log(generatePassword())

Node.js

const crypto = require('crypto')

const generatePassword = (
  length = 20,
  wishlist = '0123456789ABCDEFGHIJKLMNOPQRSTUVWXYZabcdefghijklmnopqrstuvwxyz~!@-#$'
) =>
  Array.from(crypto.randomFillSync(new Uint32Array(length)))
    .map((x) => wishlist[x % wishlist.length])
    .join('')

console.log(generatePassword())