Looping over arrays, printing both index and value

Question

I want to do something like this:

foo=( )
foo[0]=\"bar\"
foo[35]=\"baz\"
for((i=0;i<${#foo[@]};i++))
do
    echo \"$i: ${foo[$i]}\"
done
# Output:
# 0: ba         


        

Answer 1

You would find the array keys with "${!foo[@]}" (reference), so:

for i in "${!foo[@]}"; do 
  printf "%s\t%s\n" "$i" "${foo[$i]}"
done

Which means that indices will be in $i while the elements themselves have to be accessed via ${foo[$i]}