Command to get nth line of STDOUT

Question

Is there any bash command that will let you get the nth line of STDOUT?

That is to say, something that would take this

$ ls -l
-rw-r--r--@ 1 root  wh         


        

Answer 1

Try this sed version:

ls -l | sed '2 ! d'

It says "delete all the lines that aren't the second one".