Shell script “for” loop syntax

Question

I have gotten the following to work:

for i in {2..10}
do
    echo \"output: $i\"
done

It produces a bunch of lines of output: 2

Answer 1

These all do {1..8} and should all be POSIX. They also will not break if you put a conditional continue in the loop. The canonical way:

f=
while [ $((f+=1)) -le 8 ]
do
  echo $f
done

Another way:

g=
while
  g=${g}1
  [ ${#g} -le 8 ]
do
  echo ${#g}
done

and another:

set --
while
  set $* .
  [ ${#} -le 8 ]
do
  echo ${#}
done