Calculating time of execution with time() function

Question

I was given the following HomeWork assignment,

Write a program to test on your computer how long it takes to do nlogn, n2, n5, 2n, and n! additions

Answer 1

Your code is executed too fast to be detected by time function returning the number of seconds elapsed since 00:00 hours, Jan 1, 1970 UTC.

Try to use this piece of code:

inline long getCurrentTime() {
    timeb timebstr;
    ftime( &timebstr );
    return (long)(timebstr.time)*1000 + timebstr.millitm;
}

To use it you have to include sys/timeb.h.

Actually the better practice is to repeat your calculations in the loop to get more precise results.