Delay chained promise

Question

I\'m trying to do the following but it isn\'t working. How can I adjust the code to have a delay between .then and .done?

myServi         


        

Answer 1

A slightly improved version of jfriend00's approach avoids needing the pass the resolved value like this:

function delay(t) {
  return (val) => {
    return new Promise((resolve, reject) => {
      setTimeout(() => resolve(val), t)
    })
  }
}

can be used like this:

myService.new(a)
  .then(delay(60000))
  .then(function(temp) {
    return myService.get(a, temp);
  }).then(function (b) {
    console.log(b);
  });