How to catch and print the full exception traceback without halting/exiting the program?

Question

I want to catch and log exceptions without exiting, e.g.,

try:
    do_stuff()
except Exception, err:
    print(Exception, err)
    # I want to print the entir         


        

Answer 1

traceback.format_exception

If you only have the exception object, you can get the traceback as a string from any point of the code in Python 3 with:

import traceback

''.join(traceback.format_exception(None, exc_obj, exc_obj.__traceback__))

Full example:

#!/usr/bin/env python3

import traceback

def f():
    g()

def g():
    raise Exception('asdf')

try:
    g()
except Exception as e:
    exc = e

tb_str = ''.join(traceback.format_exception(None, exc_obj, exc_obj.__traceback__))
print(tb_str)

Output:

Traceback (most recent call last):
  File "./main.py", line 12, in 
    g()
  File "./main.py", line 9, in g
    raise Exception('asdf')
Exception: asdf

Documentation: https://docs.python.org/3.7/library/traceback.html#traceback.format_exception

See also: Extract traceback info from an exception object

Tested in Python 3.7.3.