Xor of string in ruby

Question

I have a string, lets say \"123|ABC|test|12345|FF\" and I want to xor the ascii value of each character and print the result in hex.

What is the simplest way?

Answer 1

In Ruby 1.8.7 or 1.9.1:

input.bytes.inject { |a,b| a ^ b }.to_s(16)