Xor of string in ruby

Question

I have a string, lets say \"123|ABC|test|12345|FF\" and I want to xor the ascii value of each character and print the result in hex.

What is the simplest way?

Answer 1

Found it...

lrc = 0
input.each_byte do | c |
    lrc ^= c
end
hexVal = lrc.to_s(16)